![]() ![]() Cross-Sectional Area of Loop = 100 cm 2 = 0.1 m 2.Thus, the magnetic moment of the current carrying loop is, 12.5 Am 2.Įxample 3: If a current-carrying loop has a magnetic moment of 25 Am 2 and the cross-sectional area of the loop is 100 cm 2 with the number of turns in the loop to be 5 then fins the current passing through the conductor. Cross-Sectional Area of Loop = 50 cm 2 = 0.If v is the orbital velocity of the electron then,Įxample 2: If a current carrying loop having current 5 A has a cross-sectional area of 20 cm 2 and the number of turns is 50 then find the magnetic dipole moment of the current carrying loop. T is the time taken by the electron to complete one revolution The current flowing through the conductor is given by the formula, The anticlockwise movement of the electron generates a conventional current in the clockwise direction. An electric current is made up of a rotating electron in a confined channel. The negatively charged electron revolves around a positively charged nucleus in a circular orbit of radius r, according to Neil Bohr’s atomic model. This magnetic moment is essential to the nature of the electron’s existence, as the electron has neither an area A (it is a point object) nor does it rotate about itself. The electron, for example, possesses a Spin Magnetic Dipole moment and acts as a magnetic dipole. Most elementary particles are magnetic dipoles by nature. Magnetic Dipole Moment of a Revolving Electron Software Engineering Interview Questions.Top 10 System Design Interview Questions and Answers.Top 20 Puzzles Commonly Asked During SDE Interviews.Commonly Asked Data Structure Interview Questions.Top 10 algorithms in Interview Questions.Top 20 Dynamic Programming Interview Questions.Top 20 Hashing Technique based Interview Questions.Top 50 Dynamic Programming (DP) Problems.Top 20 Greedy Algorithms Interview Questions.Top 100 DSA Interview Questions Topic-wise.
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